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In addition to the amount of wood calculated to be chucked, we can predict the velocity of the wood leaving the chuck and the kinetic energy of the wood.
Velocity:
@ 500 RPM the angular velocity at the Block Center of Mass is calculated by:
1 rev = 2(3.14)(13.625) = 85.6 cm
.856 m / 1 min * 1 min / 60 sec = .01427 m/s
500 * .01427 m/s = 7.135 m/sthe linear velocity at the Block Center of Mass is calculated by:
v = rw
v = (.13625)(7.135)
v = .79365 m/s
@2000 RPM the velocity at the Block Center of Mass is calculated by:
1 rev = 2(3.14)(13.625) = 85.6 cm
.856 m / 1 min * 1 min / 60 sec = .01427 m/s
2000 * .01427 m/s = 28.54 m/sthe linear velocity at the Block Center of Mass is calculated by:
v = rw
v = (.13625)(28.54)
v = 3.1746 m/s
Kinetic Energy:
Angular @ 500 RPM: KE = 1/2 Iw^2
I = SUM(mass * (radius)^2)
I = (4.0)(.075)^2 + (1.0)(13.625)^2
I = .041064
KE = ½(.041064)(5.825)^2
KE = 0.696665Angular @ 2000 RPM: KE = 1/2 Iw^2
I = SUM(mass * (radius)^2)
I = (4.0)(.075)^2 + (1.0)(13.625)^2
I = .041064
KE = ½(.041064)( 23.3)^2
KE = 11.14663Linear @ 500 RPM: KE = 1/2v^2
KE = ½( 0.793656)^2
Linear @ 2000 RPM: KE = 1/2v^2
KE = ½( 3.174625)^2
