Despite Spif's previously flawless
knowledge of uninteresting details relating to a hill
and it's conditions he forgets what type of longboard
wheels he put on today. Miraculously he forgets his
rapid approach towards the explosive truck and instead
begins to think about a way to tell if he installed his
80a polyurethane wheels or kept his 60a polyurethane
wheels from yesterday on.
Thankfully his encyclopedia of a brain comes to the
rescue once again he remembers the coefficients of
friction for his two sets of wheels. His 60a wheels he
remembered were softer than his 80a wheels and they had
a kinetic coefficient of friction on asphalt of
μk =
.8 and his kinetic coefficient of friction for his 80a
wheels on asphalt was
μk =
.6 (Spif assumes a velocity of 31.31
m/s with
his mass systems of 100
kg is enough to overcome
static friction)
Since Spif is now on a flat surface he knows gravity
will not accelerate him any more leaving friction as the
only force affecting his velocity.
To clear his mind Spif lays out the formulas needed to
calculate the distance he will travel.
To find the distance traveled
Vf ^2 =Vi^2 + 2aΔx
Vf is assumed to be 0 and
Vi
is known to be 31.31
m/s so....
0 =(31.31m/s)^2 +
2aΔx
Using basic algebra he finds
-490.15/a = Δx
To find his acceleration
a = -μk *
g
For the two different coefficients the equations are
as follows
a(60a) =
-.8 * 9.8 =
-7.84m/s
a(80a) =
-.6 * 9.8 =
-5.88m/s
So as Spif continues his slide he finds that
Δx(60a)
= -490.15 / -7.84m/s = 62.52m
and
Δx(80a)
=
-490.15 / -5.88m/s = 83.37m
As he finalizes his calculations he
gasps. Spif realizes that since the truck was only
75
m away from the bottom of the hill if he
is currently using his 80a he will momentarily be
consumed by the raging inferno that was once a
truck.
He closes his eyes and accepts his fate as he skids
to a stop approximately 12.48
m (75
m - 62.52
m
= 12.48
m) away from the blaze.
Spif breathes a sigh of relief and begins to ponder
how convenient the use of momentum is for taking him
home.