Friction and its Application in Longboard Sliding

As Spif the longboarder approaches bottom of the hill his situation looks dire as detailed in the diagram.


Furiously racking his brain over a matter of nanoseconds he tries to think of a way to use the enemy of sick speed Friction to his advantage. He remembers watching a video explaining how to do a standing board slide. Realizing he has only moments to make a decision he decides to simply go for it.
Remembering the video's instructions to simply lean back and turn his board to 90º to his current vector velocity he gets into position to begin his slide just as he meets the bottom of the hill 75m away from the catastrophe.
http://farm7.staticflickr.com/6089/6091547607_430b88df07_z.jpg
Despite Spif's previously flawless knowledge of uninteresting details relating to a hill and it's conditions he forgets what type of longboard wheels he put on today. Miraculously he forgets his rapid approach towards the explosive truck and instead begins to think about a way to tell if he installed his 80a polyurethane wheels or kept his 60a polyurethane wheels from yesterday on.

Thankfully his encyclopedia of a brain comes to the rescue once again he remembers the coefficients of friction for his two sets of wheels. His 60a wheels he remembered were softer than his 80a wheels and they had a kinetic coefficient of friction on asphalt of  μk = .8 and his kinetic coefficient of friction for his 80a wheels on asphalt was μk = .6 (Spif assumes a velocity of 31.31m/s  with his mass systems of 100kg is enough to overcome static friction)

Since Spif is now on a flat surface he knows gravity will not accelerate him any more leaving friction as the only force affecting his velocity.
To clear his mind Spif lays out the formulas needed to calculate the distance he will travel.
To find the distance traveled
Vf ^2 =Vi^2 + 2aΔx

Vf is assumed to be 0 and Vi is known to be 31.31m/s so....
0 =(31.31m/s)^2 + 2aΔx

Using basic algebra he finds
-490.15/a = Δx

To find his acceleration
a = -μk * g

For the two different coefficients the equations are as follows
a(60a) = -.8 * 9.8 = -7.84m/s
a(80a) = -.6 * 9.8 = -5.88m/s

So as Spif continues his slide he finds that
Δx(60a) = -490.15 / -7.84m/s = 62.52m
and
Δx(80a)= -490.15 / -5.88m/s = 83.37m

As he finalizes his calculations he gasps. Spif realizes that since the truck was only 75m away from the bottom of the hill if he is currently using his 80a he will momentarily be consumed by the raging inferno that was once a truck.
He closes his eyes and accepts his fate as he skids to a stop approximately 12.48m (75m - 62.52m = 12.48m) away from the blaze.

Spif breathes a sigh of relief and begins to ponder how convenient the use of momentum is for taking him home.