If both the shooter and
gun are not moving or at rest, then the force on
both the shooter and the bullet are equal. This comes from
Newton's
third law; for every action, there is an equal and opposite
reaction.
If we consider a system where the gun and shooter combine for a mass M
and the bullet has a mass m. Then when the bullet is fired from
the
gun it moves in the opposite direction with velocity v, as the
gun/shooter withwith new velocity V. However, due to the law of
conservation of momentum
we get the equation MV + mv = 0 (1) since the magnitudes of their
momenta must be equal to each other. And since force is equal to the
rate of change in momentum and the systems initial momentum are both 0,
the force that is acted on the bullet is the same as the force acted on
the shooter. Having said this it brings up the point of people
being
flung 20 feet in the air and through windows in the movies.
Although
this makes the movies interesting and fun to watch it is simply not
true. If it were the case then the shooter would also be flung
off
their feet equally as the person being shot.
The small mass of the bullet, compared to that of the shooter, allows for significantly more kinetic energy to be passed on to the bullet than to the shooter. The kinetic energy for the two systems are ½ MV2 for the shooter and ½ mv2 for the bullet. The energy passed on to the shooter can be written as:
½ MV2 = 1/2M (mv/M)2 = (m/M) (½ mv2)
Since the mass of the
bullet is so much smaller than the shooter much more kinetic energy is
transfered to the bullet than the shooter. Once a bullet is shot
out of the gun its energy immediately starts to drop until it hits the
target where it transfers what is left.