The Physics of the Bench Press
Much like the Squat, the factor that makes the Bench Press so effective
is the push directly against the downward pull of gravity. The same laws
of Physics applied to the Squat on the previous page can be applied here
as well. But there are other concepts that can be applied to both lifts.
One such concept is the concept of work. This is not work in the
sense that most people know. Work can be defined as:
Work W done on an object by an agent exerting a constant force on
the object is the product of the component of the force in the direction
of the displacement and the magnitude of the displacement.
In equation form : Fd cos(x) where F=the applied force, d=displacement,
and x=the angle the force acts at.
For example, take the man benching in the picture below. He applies a
force of 2500 N on the weight and displaces the weight .5 meters. How
much work did he do on the weights?
(www.roxboro.net)
The force applied is 2500 N and the displacement is .5 m. Since the force
is in the direction of the displacement, the angle is 0 degrees and COs(0)
=1 so
FD=2500 N * .5m = 1250N*m
The Newton-meter is used so much that it has been given the name Joule(J),
so the Work done by the man is 1250 J.
Another physical concept that can be applied to the bench press is power.
Power in the physical sense can be defined as work over time or:
Power P =Work(W)/Time interval(T)
It takes the man in the picture 2 seconds to raise the bar from his chest
to his initial position(.5 meters). From the last question, we know that
the work done by the lifter is 1250 J. If the time interval is 2 seconds,
then:
P = 1250J/2s = 625 J/s
Joules per second are also known as watts (W), so the total power of
the lifter is 625 W.
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