So to solve this the
equation must be set up as follows
Solve for the distance by solving for
finding the vector components.
y=5sin(45)=5rt(2)/2 and
x=5cos(45)=5rt(2)/2
with that information we can
solve for the time it takes for y to reach its max height.
We know that the velocity initial in the y equals
5rt(2)/2, the velocity final equals 0, and that
acceleration acts with a force of -9.81 m/s^2.
Using the first kinematic equation from above
-5rt(2)/2=-9.8t
by dividing by -9.81 we obtain t to equal .36 sec. We
double this to find the total flight time. So the total
flight time is actually .72 sec!
The total distance is then simply found by the equation
DISTANCE =RATE * TIME
DISTANCE = The x component * .72sec
Distance = 5rt(2)/2*.72 = 2.54m
Conclusion- He hits his side of the table and looses the
point!
Lets say that a Ping Pong
player wants to hit the ball on to the other side of the
table. He hits the ball at 5 m/sec at a 45 deg angle from
3meters away from the net and he makes contact with the
ball at table level. Does he make it on the table? ( The
length of a standard Ping pong table is 2.74
m)
