Godzilla: In Flight!
used his atomic ray breath weapon to give chase to Hedorah. Using
his power as a jet turbine, he used his power as a jet-turbine to fly
backwards through the air in pursuit. The incarnation of Godzilla used at the
time is given by the studio, Toho, to be approximately 50 meters (165 ft.)
in height, and conservatively weighing in at 20,000 tons (1.8*10^7 kilograms).
The
force Godzilla exerts on the ground, ignoring air-pressure,
would be: Fy=ma
where the acceleration is due to the force of gravity. Therefore
F=1.8*10^7kg*-9.8m/s^2 = -1.75*10^8 Newtons.
where the acceleration is due to the force of gravity. Therefore
F=1.8*10^7kg*-9.8m/s^2 = -1.75*10^8 Newtons.
This is already a huge
amount of force, but Godzilla is not merely breaking his
hold on gravity. Using some quick measurements, it
appears as if he travels approximately 6.5 meters
upwards after 10 seconds from rest. Using kinematics
equations.
xf=xi + vi*t + .5*a*t^2
~~
2*6.5m / 10s^2= a = .13 m/s^2
Once again using Fy=ma, and assuming that the force emitted from his ray is constant
~~
2*6.5m / 10s^2= a = .13 m/s^2
Once again using Fy=ma, and assuming that the force emitted from his ray is constant
Fy=1.8*10^7kg*.13m/s^2 = -1.75*10^8 + Fray1*sin(70)
~~
Fray1 = 1.89*10^8 Newtons
Godzilla eventually levels off and begins flying completely horizontally, changing the angle of his breath to about 25 degrees with respect to the ground. This means that the output of force given by his breath in the y direction is equivalent to the force gravity exerts on him, 1.75*10^8N
Fy=ma=0=-1.75*10^8N+Fray2*sin(25)
Fray2=4.14*10^8N
So between the change in the angle of his breath weapon, he begins to exert a bit more than twice as much force as before to stay afloat. Using this same force to calculate acceleration in the horizontal direction.
Fx=ma=1.8*10^7kg*a=4.14*10^8cos25
~~
a=20.85m/s^2
Which is quite an impressive acceleration for such a large creature. Given that he flies for about 30 seconds, his final velocity given kinematics equations is.
vf=vi+a*t
Assuming his initial velocity in the x direction is negligible
vf=20.85m/s^2*30s = 625.4m/s or 1398 miles per hour.
Which is an appropriately ridiculous speed for such a
ridiculous event. Even if we were to account for
forces such as Air Resistance which would certainly not be
negligible given the large surface area, or obvious
rotational kinematics that would ensue from such a
propulsion setup, this is still an entirely gigantic rate
of movement.