So, in order to kill the ooze bear, we know
that we only really need to know the diameter of a
projectile, and how
far that projectile penetrates into the ooze bear.
Because we know that an ooze bear disassociates into
a fluid in reaction
to trauma, the distance a projectile goes through an
ooze bear can be calculated by how far it can travel
through a fluid
of the given characteristics. For that, we start
with the equation dictating force of drag, easily
found in our textbook
on page 145.
F=.5*C*p*A*(v^2)
where C=the drag coefficient, p=material density,
A=the cross section of the projectile, and
v=velocity.
To determine the penetration of the projectile, we
consider its kinetic energy, or rather the change in
kinetic energy,
which is known to be force times distance, or, in
this case:
dE=-.5*C*p*A*(v^2)*dx
and of course the sign changes here because the
change in energy of our projectile will be negative.
The equation we are left with brings us closer to a
productive equation, but velocity is problematic. It
can be said,
however, that v^2=(2*E)/m, from our understanding of
kinetic energy, and the equation again changes to
dE=-C*(E/m)*p*A*dx
This equation is now very close to being useful,
except that it needs to be integrated, and the value
of energy consolidated,
which all sounds very tedious except that this
is
the differential equation for exponential decay,
written, in this case, as
E=E
0*e^(r*x)
where r=-C*A*p*(1/m), the constant of our equation,
E
0 is initial energy, and x
is of course distance traveled. To prove this
we rewrite dE as
dE=r*dx*E
then substitute in E
0*e^(r*x)
for E
dE=r*dx*E
0*e^(r*x)
Which we easily see is definitely the derivative of
our energy equation, in the general form of
exponential decay! Now we re-write this equation in
its expanded form, because it is important and
useful for us to know which constants we need to
define.
E=E
0*e^(-C*A*p*(1/m)*x)
And we also note that we now have the following list
of constants: E
0=initial
energy, C=the drag coefficient, p=the material
density, A=the cross section of the projectile,
m=projectile mass, and finally x=distance traveled.
Note that by the equation we have described, there
is technically no limit on the theoretical
penetration of a round when the behavior of the body
it is passing through is hydrodynamic. Of course,
there is a limit past which round penetration can no
longer be calculated using hydrodynamic performance,
and in this case that limit is when the pressure
exerted by the round onto the oozebear is less than
F/A=50,000Pa
And, with all of this done, you can finally begin to
analyze the performance of several different
munitions, as since the only practical damage we
care about is the volume of liquefied oozebear any
further trajectory that can be mapped of our
projectiles is irrelevant.