Using the Llewellyn glacier
as an example:
- m = volume times density of ice (918kg/meters cubed)
- m = 70,000,000m^3 x 918 = 64260000000kg
- K = (.5)(64260000000kg)(.00000277m/s)^2 = .2479joules
- P = K/t = .2479joules/1sec = .2479 watts
This can be compared to something more tangible such as a caterpillar
D-10 dozer which puts out 580 Hp which is equivalent to .7775 watts.
(www.caterpillar.com)
- If a glacier take 100,000 years to create a large glacier
valley this would be 781777440000 watts of power.
- It would take a single caterpillar D-10 31,885
years to produce this much energy.
(www.caterpillar.com)