For example, a kick with a velocity of 90 ft/s (27.4 m/s) at an angle
     of 30 degrees will have the following values:

1. Vertical and horizontal components of velocity:
   • V_x = V cos(theta) = (27.4 m/s) cos (30 degrees) = (27.4 m/s) (0.0.87) = 23.7 m/s
   • V_y = V sin(theta) = (27.4 m/s) sin (30 degrees) = (27.4 m/s) (0.5) = 13.7 m/s
2. Hang-time:
   • t_total = (0.204V_y) = {0.204 (13.7m/s)} = 2.80 s.
3. Maximum range:
   • x_max = V_x t_total = (23.7 m/s)(2.80 s) = 66.4 m
   • 1 m = 1.09 yd
   • x_max = 72 yd
4. Time at peak height:
   • t_1/2 = 0.5 t_total = (0.5)(2.80 s) = 1.40 s
5. Peak height:
   • y_max = V_y(t_1/2) - 0.49(t_1/2)² = [{(13.7 m/s)(1.40 s)} - {0.49(1.40 s)²}] = 18.2 m
   • 1 m = 3.28 ft
   • y_max = 59.7 ft

     If we do the calculations for a punt with the same velocity, but an
     angle of 45 degrees, then we get a hang-time of 3.96 s, a
     maximum range of 76.8 m (84 yd), and a peak height of 36.5 m.
     If we change the angle of the kick to 60 degrees, we get a hang
     -time of 4.84 s, a maximum range of 66.3 m, and a peak height
    of 54.5 m. You see that as the angle of the kick gets steeper, the
     ball hangs longer in the air and goes higher.